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Author: drcgian
Date: 31-10-2002, 18:32
| There will be one group stage with 36 teams divided in 6 groups (6 teams in each group). Home and away matches will be played, a total of 10. a) *16 teams qualify -6 winners -6 runners up -4 best third placed teams, to decide which 3rd placed team is best only the matches with the teams finished in position 1-4 counts (a total of 6 matches). *the 16 teams play 8 knock-out matches and 8 winners qualify and so on till the final b) * 12 teams qualify -6 winners + 6 runners up winners are seeded, runners up are unseeded and 6 qualify from knock-out matches *those play again in knock out (home-away) matches and 3 teams qualify. Then the winner go to the Final Week. Final week has 3 games. Sunday-Wednesday-Sunday. 2 of the 3 will be drawn to play the Game1 on Sunday on Neutral Ground-1. These lets say are Team1 and Team2. Then Team3 will play on Wednesday in Neutral Ground-2 with the loser of Game1. The winner of Game1 will face Team3 on 2nd Sunday in Neutral Ground-3. After the calculation of pts etc. the 1st will be the winner who will qualify for UCL next year and the 2nd will qualify for the UC next year.
How do you find that idea? |
Author: eyal
Date: 31-10-2002, 19:40
| the second one i way too complicated |
Author: eyal
Date: 31-10-2002, 19:42
| and the first one makes the teams play too many games i think the big problem today is that there are too many matches a good player has too play every year a top player has to play maybe like 60-70 games |
Author: krdeluxe
Date: 04-11-2002, 15:30
| In both formats teams could be qualified for the next round after 7 or 8 matches, so the last 2 or 3 matches these teams will play with substitutes. Also too much games. For the second format: I like a final over 1 game. |
Author: drcgian
Date: 09-11-2002, 12:39
| Too many matches again, but let's hold the point that 3 teams reach the final and not only 2. |
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