@Lyonnais @fabiomh
What about we use a real Swiss system? We don't need to mess with TV pairings etc.
Alternatively this may be of use https://en.m.wikipedia.org/wiki/2019–20 ... qualifying
Prediction game - Rules and discussion thread
- Jackson Harrison
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This is exactly the goal. The only constraint is matching two opponents from each pot.Jackson Harrison wrote: ↑Sat Nov 25, 2023 13:43 @Lyonnais @fabiomh
What about we use a real Swiss system? We don't need to mess with TV pairings etc.
Alternatively this may be of use https://en.m.wikipedia.org/wiki/2019–20 ... qualifying
Some comment of mine:
- Of course we need to have an even number if total players - the virtual average can help.
- The schedule is simple if each pot has the same number of players and with an even number of players per pot.
if not, we may need some correction.
some example and some hypothesis of solution:
48 partecipants:
- CL/EL: 4 pots x 12 players per pot: no issue
- ECL: 3 pots x 16 players per pot: no issue
47 partecipants:
- CL/EL: (+1 virtual avg) like 48 partecipants
- ECL: (+1 virtual avg) like 48 partecipants
46 partecipants:
- CL/EL:
sol 1: (+2 virtual avg) like 48 partecipants
sol 2: no virt avg: 4 pots (A 11 players, B 12, C 12, D 11) : schema similar to the one in the link suggested by @Jackson Harrison
- ECL:
sol 1: (+2 virtual avg): like 48 partecipants
sol 2: no virt avg: 3 pots (A 16 players, B 14, C 16) : schema similar to the one in the link ? to be found for 3 pots
45 partecipants:
- CL/EL:
sol 1: (+3 virtual avg) like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
- ECL:
sol 1: (+3 virtual avg): like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
44 partecipants:
- CL/EL:
sol 1: (+4 virtual avg) like 48 partecipants
sol 2: (no virtual avg): a "simple schema corrected", no possibility to have MDs with only intra-pot matches
- ECL:
sol 1: (+4 virtual avg): like 48 partecipants
sol 2: (+2 virtual avg): like Sol 2 for 46 partecipants
sol 3: (no virtual avg): 3 potes (A 14 players, B 16, C 14): schema similar to the one in the link ? to be found for 3 pots
...
Hope for more partecipants in the next Prediction Game
- Jackson Harrison
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- Posts: 6573
- Joined: Sat Dec 31, 2022 17:25
- Location: England
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Or maybe include more virtavg to make up numbersfabiomh wrote: ↑Sat Nov 25, 2023 15:53This is exactly the goal. The only constraint is matching two opponents from each pot.Jackson Harrison wrote: ↑Sat Nov 25, 2023 13:43 @Lyonnais @fabiomh
What about we use a real Swiss system? We don't need to mess with TV pairings etc.
Alternatively this may be of use https://en.m.wikipedia.org/wiki/2019–20 ... qualifying
Some comment of mine:
- Of course we need to have an even number if total players - the virtual average can help.
- The schedule is simple if each pot has the same number of players and with an even number of players per pot.
if not, we may need some correction.
some example and some hypothesis of solution:
48 partecipants:
- CL/EL: 4 pots x 12 players per pot: no issue
- ECL: 3 pots x 16 players per pot: no issue
47 partecipants:
- CL/EL: (+1 virtual avg) like 48 partecipants
- ECL: (+1 virtual avg) like 48 partecipants
46 partecipants:
- CL/EL:
sol 1: (+2 virtual avg) like 48 partecipants
sol 2: no virt avg: 4 pots (A 11 players, B 12, C 12, D 11) : schema similar to the one in the link suggested by @Jackson Harrison
- ECL:
sol 1: (+2 virtual avg): like 48 partecipants
sol 2: no virt avg: 3 pots (A 16 players, B 14, C 16) : schema similar to the one in the link ? to be found for 3 pots
45 partecipants:
- CL/EL:
sol 1: (+3 virtual avg) like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
- ECL:
sol 1: (+3 virtual avg): like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
44 partecipants:
- CL/EL:
sol 1: (+4 virtual avg) like 48 partecipants
sol 2: (no virtual avg): a "simple schema corrected", no possibility to have MDs with only intra-pot matches
- ECL:
sol 1: (+4 virtual avg): like 48 partecipants
sol 2: (+2 virtual avg): like Sol 2 for 46 partecipants
sol 3: (no virtual avg): 3 potes (A 14 players, B 16, C 14): schema similar to the one in the link ? to be found for 3 pots
...
For example 45 player:
Pot 1: Top 12
Pot 2: Next 11+virgavg of all pot 2
Pot 3: Next 11+virgavg of all pot 3
Pot 4: Next 11+virgavg of all pot 4
What are your thoughts on a real Swiss System?
the "simple schema corrected" for 44 partecipants divided in 4 pots (A, B, C, D)
based on simple schema posted by @Lyonnais (perfect for 48 partecipants):
I renamed 1,2,3,4 into A,B,C,D. The teams into A1, A2, ... A11, B1, B2, ... and so on
MD2/MD6: A v C, B v D
MD3/MD7: A v B, C v D
MD4/MD8: A v A, B v B, C v C, D v D
Correction:
MD1: A1-D1, A2-D2, ... A10-D10, same for B-C (A11-D11, A6-D6, B11-C11, B6-D6 replaced by A11-A6, B11-B6, C11-C6, D11-D6)
MD2: A1-C8, A2-C9, ..., A4-C11, A5-C1, ..., A11-C7, same for B-D
MD3: A1-B10, A2-B11, A3-B1, ... A11-B9, same for C-D
MD4: A1-A2, A3-A4, ..., A9-A10, [no A11] same for B-B, C-C, D-D (+ A11-D11 + B11-C11)
MD5: A1-D4, A2-D5, ..., A8-D11, A9-D1, A10-D2, A11-D3, same for B-C
MD6: A1-C5, A2-C6, ..., A7-C11, A8-C1, ..., A11-C4, same for B-D
MD7: A1-B9, ... A3-B11, A4-B1, ..., A11-B8, same for C-D
MD8: A1-A7, A2-A9, A3-A11, A4-A8, A5-A10, [no A6], same for B-B, C-C, D-D (+A6-D6 + B6-C6)
based on simple schema posted by @Lyonnais (perfect for 48 partecipants):
I renamed 1,2,3,4 into A,B,C,D. The teams into A1, A2, ... A11, B1, B2, ... and so on
MD1/MD5: A v D, B v C
MD2/MD6: A v C, B v D
MD3/MD7: A v B, C v D
MD4/MD8: A v A, B v B, C v C, D v D
Correction:
MD1: A1-D1, A2-D2, ... A10-D10, same for B-C (A11-D11, A6-D6, B11-C11, B6-D6 replaced by A11-A6, B11-B6, C11-C6, D11-D6)
MD2: A1-C8, A2-C9, ..., A4-C11, A5-C1, ..., A11-C7, same for B-D
MD3: A1-B10, A2-B11, A3-B1, ... A11-B9, same for C-D
MD4: A1-A2, A3-A4, ..., A9-A10, [no A11] same for B-B, C-C, D-D (+ A11-D11 + B11-C11)
MD5: A1-D4, A2-D5, ..., A8-D11, A9-D1, A10-D2, A11-D3, same for B-C
MD6: A1-C5, A2-C6, ..., A7-C11, A8-C1, ..., A11-C4, same for B-D
MD7: A1-B9, ... A3-B11, A4-B1, ..., A11-B8, same for C-D
MD8: A1-A7, A2-A9, A3-A11, A4-A8, A5-A10, [no A6], same for B-B, C-C, D-D (+A6-D6 + B6-C6)
Hope for more partecipants in the next Prediction Game
48 is the perfect number; from 45 to 44 virtual avg can easily used to increase the number to 48.Jackson Harrison wrote: ↑Sat Nov 25, 2023 16:15Or maybe include more virtavg to make up numbersfabiomh wrote: ↑Sat Nov 25, 2023 15:53This is exactly the goal. The only constraint is matching two opponents from each pot.Jackson Harrison wrote: ↑Sat Nov 25, 2023 13:43 @Lyonnais @fabiomh
What about we use a real Swiss system? We don't need to mess with TV pairings etc.
Alternatively this may be of use https://en.m.wikipedia.org/wiki/2019–20 ... qualifying
Some comment of mine:
- Of course we need to have an even number if total players - the virtual average can help.
- The schedule is simple if each pot has the same number of players and with an even number of players per pot.
if not, we may need some correction.
some example and some hypothesis of solution:
48 partecipants:
- CL/EL: 4 pots x 12 players per pot: no issue
- ECL: 3 pots x 16 players per pot: no issue
47 partecipants:
- CL/EL: (+1 virtual avg) like 48 partecipants
- ECL: (+1 virtual avg) like 48 partecipants
46 partecipants:
- CL/EL:
sol 1: (+2 virtual avg) like 48 partecipants
sol 2: no virt avg: 4 pots (A 11 players, B 12, C 12, D 11) : schema similar to the one in the link suggested by @Jackson Harrison
- ECL:
sol 1: (+2 virtual avg): like 48 partecipants
sol 2: no virt avg: 3 pots (A 16 players, B 14, C 16) : schema similar to the one in the link ? to be found for 3 pots
45 partecipants:
- CL/EL:
sol 1: (+3 virtual avg) like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
- ECL:
sol 1: (+3 virtual avg): like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
44 partecipants:
- CL/EL:
sol 1: (+4 virtual avg) like 48 partecipants
sol 2: (no virtual avg): a "simple schema corrected", no possibility to have MDs with only intra-pot matches
- ECL:
sol 1: (+4 virtual avg): like 48 partecipants
sol 2: (+2 virtual avg): like Sol 2 for 46 partecipants
sol 3: (no virtual avg): 3 potes (A 14 players, B 16, C 14): schema similar to the one in the link ? to be found for 3 pots
...
For example 45 player:
Pot 1: Top 12
Pot 2: Next 11+virgavg of all pot 2
Pot 3: Next 11+virgavg of all pot 3
Pot 4: Next 11+virgavg of all pot 4
What are your thoughts on a real Swiss System?
Below 45, you cannot use too many virtual average players, considering also that probably some players will retire during the competition and you are forced to add some more virtual avg player.
I don't know very well the real Swiss System, I have just read a bit on wiki. It should have not pre-fixed schedule, but it should be determined every MD, based on the ranking, and avoiding that two palyers match twice. Too complex,and it needs some specific computer program to be run after each MD.
IMHO not suitable for our simple game and goals. We want to enjoy and need a clear, simple and transparent method.
Hope for more partecipants in the next Prediction Game
- Jackson Harrison
- Senior Member
- Posts: 6573
- Joined: Sat Dec 31, 2022 17:25
- Location: England
- Contact:
Websites like challenge.com operate these systems smoothly.fabiomh wrote: ↑Sat Nov 25, 2023 16:3448 is the perfect number; from 45 to 44 virtual avg can easily used to increase the number to 48.Jackson Harrison wrote: ↑Sat Nov 25, 2023 16:15Or maybe include more virtavg to make up numbersfabiomh wrote: ↑Sat Nov 25, 2023 15:53
This is exactly the goal. The only constraint is matching two opponents from each pot.
Some comment of mine:
- Of course we need to have an even number if total players - the virtual average can help.
- The schedule is simple if each pot has the same number of players and with an even number of players per pot.
if not, we may need some correction.
some example and some hypothesis of solution:
48 partecipants:
- CL/EL: 4 pots x 12 players per pot: no issue
- ECL: 3 pots x 16 players per pot: no issue
47 partecipants:
- CL/EL: (+1 virtual avg) like 48 partecipants
- ECL: (+1 virtual avg) like 48 partecipants
46 partecipants:
- CL/EL:
sol 1: (+2 virtual avg) like 48 partecipants
sol 2: no virt avg: 4 pots (A 11 players, B 12, C 12, D 11) : schema similar to the one in the link suggested by @Jackson Harrison
- ECL:
sol 1: (+2 virtual avg): like 48 partecipants
sol 2: no virt avg: 3 pots (A 16 players, B 14, C 16) : schema similar to the one in the link ? to be found for 3 pots
45 partecipants:
- CL/EL:
sol 1: (+3 virtual avg) like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
- ECL:
sol 1: (+3 virtual avg): like 48 partecipants
sol 2: (+1 virtual avg): like Sol 2 for 46 partecipants
44 partecipants:
- CL/EL:
sol 1: (+4 virtual avg) like 48 partecipants
sol 2: (no virtual avg): a "simple schema corrected", no possibility to have MDs with only intra-pot matches
- ECL:
sol 1: (+4 virtual avg): like 48 partecipants
sol 2: (+2 virtual avg): like Sol 2 for 46 partecipants
sol 3: (no virtual avg): 3 potes (A 14 players, B 16, C 14): schema similar to the one in the link ? to be found for 3 pots
...
For example 45 player:
Pot 1: Top 12
Pot 2: Next 11+virgavg of all pot 2
Pot 3: Next 11+virgavg of all pot 3
Pot 4: Next 11+virgavg of all pot 4
What are your thoughts on a real Swiss System?
Below 45, you cannot use too many virtual average players, considering also that probably some players will retire during the competition and you are forced to add some more virtual avg player.
I don't know very well the real Swiss System, I have just read a bit on wiki. It should have not pre-fixed schedule, but it should be determined every MD, based on the ranking, and avoiding that two palyers match twice. Too complex,and it needs some specific computer program to be run after each MD.
IMHO not suitable for our simple game and goals. We want to enjoy and need a clear, simple and transparent method.
It's less complex than this, how do we plan to determine fixtures on this? I'm going to run a mock based on this season to see how it would've worked.
I would prefer a method with:
a) pots, as per continuity with the past
b) prefixed schedule for all the 8MDs, known as soon as possible, before the first MD
a) pots, as per continuity with the past
b) prefixed schedule for all the 8MDs, known as soon as possible, before the first MD
Hope for more partecipants in the next Prediction Game
- Jackson Harrison
- Senior Member
- Posts: 6573
- Joined: Sat Dec 31, 2022 17:25
- Location: England
- Contact: